tanx + cotx = 2

By Admin 19/11/2023 0

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1

∫{1+2 tan x(tan x+sec x)}1/2 dx=

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2

∫dx4+5sin2xdx is equal đồ sộ.

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3

The integral of ∫1−sinxcos2xdx is

(a) tanx+secx+c       (b) tanx−secx+c
(a) secx−tanx+c       (b) tanx−lnsecx+c

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If ∫esin x[xcos3x−sinxcos2x]dx=esin xf(x)+c where c is constant of integration, then f(x)=

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If f(x)=(logcotxtan x)(logtanxcot x)−1+tan−1(x√(4−x2)) then f'(0) is equal to

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