naalo2 + naoh

To balance the equation NaAlO2 + NaOH = Al(OH)3 + Na2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to tát represent the unknown coefficients.

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a NaAlO2 + b NaOH = c Al(OH)3 + d Na2O

Step 2: Create a System of Equations

Create an equation for each element (Na, Al, O, H) where each term represents the number of atoms of the element in each reactant or product.

Na:	1a	+	1b	=	0c	+	2d
Al:	1a	+	0b	=	1c	+	0d
O:	2a	+	1b	=	3c	+	1d
H:	0a	+	1b	=	3c	+	0d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to tát solve for each variable.

  • 1a + 1b - 2d = 0
  • 1a - 1c = 0
  • 2a + 1b - 3c - 1d = 0
  • 1b - 3c = 0

Use your graphing calculator's rref() function (or an online rref calculator) to tát convert the following matrix into reduced row-echelon-form:

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[ 1	 1	 0	-2	0]
[ 1	 0	-1	 0	0]
[ 2	 1	-3	-1	0]
[ 0	 1	-3	 0	0]

The resulting matrix can be used to tát determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result to tát get the lowest, whole integer values.

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  • a = 1 (NaAlO2)
  • b = 3 (NaOH)
  • c = 1 (Al(OH)3)
  • d = 2 (Na2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

NaAlO2 + 3 NaOH = Al(OH)3 + 2 Na2O

Reactants Products
Na44✔️
Al11✔️
O55✔️
H33✔️

Since there is an equal number of each element in the reactants and products of NaAlO2 + 3NaOH = Al(OH)3 + 2Na2O, the equation is balanced.