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Crude calcium carbide, CaC2, is made in an electric furnace by the reaction, CaO+3C→CaC2+CO
The product contains 64% CaC2 and 36% unreacted CaO.
(Given that molecular weight of Ca = 40, C =12, O = 16)
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What is the amount of heat to tướng be supplied to tướng prepare 128 g of CaC2 by using CaCO3 and followed by reaction with carbon. Reactions are:
CaCO3(s)→CaO (s)+CO2 (g); △Ho=42 .8 kcal
CaO (s)+3C (s)→CaC2+CO (g); △Ho=111 kcal
One mole each of CaC2, Al4C3 and Mg2C3 react with H2O in separate open flasks at 25oC. Numerical value of the work done by the system is in the order:
Given reactions:
CaC2(s)+2H2O(l)→Ca(OH)2(s)+C2H2(g)
Al4C3(s)+12H2O(l)→4Al(OH)3(s)+3CH4(g)
Mg2C3(s)+4H2O(l)→2Mg(OH)2(s)+CH3−C≡CH(g)
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What is the amount of heat to tướng be supplied to tướng prepare 128 g of CaC2 by using CaCO3 and followed by reaction with carbon. Reactions are:
CaCO3(s)→CaO (s)+CO2 (g); △Ho=42 .8 kcal
CaO (s)+3C (s)→CaC2 (s)+CO (g); △Ho=111 kcal
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NH3 is formed in the following steps
I. Ca+2C→CaC2 50% yield
II. CaC2+N2→CaCN2+C 100% yield
III. CaCN2+3H2O→2NH3+CaCO3 50% yield
To obtain 2 moles NH3, calcium required is:
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