# al2o3 al2so43

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let bầm know where is Al2O3 in Al2(SO4)3 containing from? as we know there is 17-18% Al2O3 in commonly Al2(SO4)3 product. is it because low convertion of reaction Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O, or something?

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if i using Al(OH)3 vĩ đại convert Al2(SO4)3, 2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O, is it still happen 17-18% containing Al2O3 in Al2(SO3)3 because dehydration reaction of 2Al(OH)3 = Al2O3 + 3H2O?

AChem

asked Apr 13, 2020 at 22:02

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You are referring vĩ đại very old analytical methods and analysis. In older times, many analyses were reported as oxides. This practice comes from gravimetric analysis. This practice continues today in fertilizers analysis and in some other industries. Coming vĩ đại your question, there is no Al$_2$O$_3$ unit per se however the purity of aluminum sulfate may be quoted as aluminum oxide. Just bởi a simple mole calculation using the relation vĩ đại determine the actual purity of aluminium sulfate. Just keep in mind, quoting percentage of oxides is purely historical, but you can easily bởi calculations as follows.

1 mol Al$_2$O$_3$ $\equiv$ 1 mol Al$_2$SO$_4$ $\equiv$ 1 mol Al$_2$SO$_4$. $x$H$_2$O

answered Apr 14, 2020 at 0:54

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